6x^2+49x=98

Solution for 6x^2+49x=98 equation:

6x^2+49x=98

We move all terms to the left:

6x^2+49x-(98)=0

a = 6; b = 49; c = -98;
Δ = b2-4ac
Δ = 492-4·6·(-98)
Δ = 4753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4753}=\sqrt{49*97}=\sqrt{49}*\sqrt{97}=7\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-7\sqrt{97}}{2*6}=\frac{-49-7\sqrt{97}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+7\sqrt{97}}{2*6}=\frac{-49+7\sqrt{97}}{12}
$